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5f^2+3f-8=0
a = 5; b = 3; c = -8;
Δ = b2-4ac
Δ = 32-4·5·(-8)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-13}{2*5}=\frac{-16}{10} =-1+3/5 $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+13}{2*5}=\frac{10}{10} =1 $
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